quote:Original post by petewood
As frunny says, change the function to:

void ReportType(const T& = T())

It's a kludge but it works.

Not sure what it would be useful for (c:

// used to call Pop<int>(); untill noticed problemtemplate<class T> void Pop(){ spos -= sizeof(T); delete (T*)svars[spos]; }// so im goin call it like this then:int t; // so type and size can be knownPop(t); 

quote:Original post by siaspete
What happens when you use

template <typename T>instead of    template <class T>

Maybe it won''t help, but you can give it a go.

Why you shouldn''t use iostream.h - ever! | A Good free online C++ book

// kinda wierd stuff for me... but workstemplate<class T> void ReportType(const T& = T()) { if(typeid(T) == typeid(string))	 cout<<"It's a string! "<<endl; else if(typeid(T) == typeid(int))	 cout<<"It's a int! "<<endl;}int main(){ReportType<int>();ReportType<string>();return 1;}

template<class T> void ReportType(const T& = T())