void main() {
double number = 0.0;
number = 1.6;
// here to find out if .6 is greater than or less than .5, how would I determine that
}
[edited by - BlueDev on September 1, 2003 2:43:56 PM]
Round up/down function
Author
Hello,
Is there a possible way to find out if my numbers decimal point is greater than or less than .5 and then take the neccessary steps to round up or round down to the nearest number, example:
[edited by - BlueDev on September 1, 2003 2:43:56 PM]
[edited by - BlueDev on September 1, 2003 2:43:56 PM]
You´re lucky! I´ve just wrote one a couple of hours ago!!
Hope it helps!
--Ignacio Liverotti
iliverotti@hotmail.com
inline float FixValue(float Value){ double dInteger,dFraction; dFraction = modf(Value,&dInteger); if(dFraction<0.0) { if(dFraction < -0.5) return ((float)dInteger-1.0f); else return (float)dInteger; } // End if. else { // fFraction > 0. if(dFraction > 0.5) return ((float)dInteger+1.0f); else return (float)dInteger; } // End else.} // End FixValue(). Hope it helps!
--Ignacio Liverotti
iliverotti@hotmail.com
Author
Wow thanks, you just saved me days of trying to figure this out, many thanks Ignacio Liverotti.
- BlueDev
- BlueDev
If you have a decent compiler (as I think it's a c99 addition) you could use "round". If not I think that this will also work (it's a bit shorter) :
This should round correctly (+0.5 -> +1.0 and -0.5 -> -1.0)
[edited by - Robot guy on September 2, 2003 4:43:32 AM]
double round(double val) { return (val > 0.0) ? floor(val + 0.5) : ceil(val - 0.5);}This should round correctly (+0.5 -> +1.0 and -0.5 -> -1.0)
[edited by - Robot guy on September 2, 2003 4:43:32 AM]
Floating point values are simply truncated when converting to an int (at least in common languages like Java or C/C++). So (int) (value + 0.5) will behave as you want it to behave.
[edited by - BitMaster on September 2, 2003 4:52:36 AM]
[edited by - BitMaster on September 2, 2003 4:52:36 AM]
This topic is closed to new replies.
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