void tileslist::refresh_tlist(HWND list)
{
list <stTile*>::iterator it;
SendMessage(list,LB_RESETCONTENT,0,0);
for(it=tiles.begin();it!=tiles.end();it++)
SendMessage(list,LB_ADDSTRING,0,(LPARAM)(*it)->dat.name);
}
Strange problem....
Author
I have a very strange problem, I copy + pasted some code from another member function of a class when I was making one, and tried to compile. Both MSVC++ 6 and g++ are giving me strange errors about it:
"Iterator is not a member of global namespace"
-- did you try putting a using namespace std; line in?
Also, if you would post the other function in which it works correctly, it might be easier to find the error.
-- did you try putting a using namespace std; line in?
Also, if you would post the other function in which it works correctly, it might be easier to find the error.
SendMessage(list,LB_ADDSTRING,0,(LPARAM)(*it)->dat.name);
^ should be .
Iterators act like pointers, if you de-reference them, you no longer have a pointer, you have the object you''re pointing at, and therfore, must use . notation to access "dat" member.
Tony
^ should be .
Iterators act like pointers, if you de-reference them, you no longer have a pointer, you have the object you''re pointing at, and therfore, must use . notation to access "dat" member.
Tony
Author
Yes I know iterators act like pointers:
Also I don't really care much about the stuff after the line in question (the declaration of the iterator), the problem I am having is in the declaration of the iterator.
This same code as I said works in another member function, in the same file (actually that function ends the next line above this one's beginning), and yes there is a using namespace std in there aswell.
I've been trying to get this for about an hour now, so I've thought of such things
.
Thanks for help, ~SPH
P.S. Sorry if this post seemed a bit angered... I have everlasting resent for the cowardly "Anonymous Poster"... :-D
[edited by - ShmeeBegek on September 2, 2003 4:41:05 PM]
class tileslist{private: list <stTile*> tiles; int tc,stc;public: tileslist(); ~tileslist(); bool add_tile(); bool add_subtile(); bool del_tile(); bool del_subtile(); bool edit_tile(); bool move_tile(int dir); bool move_subtile(int dir); void set_tilecur(int cur); void set_subtilecur(int cur); // Invalidates tile cursor void refresh_tlist(HWND list); // Invalidates subtile cursor void refresh_stlist(HWND list);};Also I don't really care much about the stuff after the line in question (the declaration of the iterator), the problem I am having is in the declaration of the iterator.
This same code as I said works in another member function, in the same file (actually that function ends the next line above this one's beginning), and yes there is a using namespace std in there aswell.
I've been trying to get this for about an hour now, so I've thought of such things
.Thanks for help, ~SPH
P.S. Sorry if this post seemed a bit angered... I have everlasting resent for the cowardly "Anonymous Poster"... :-D
[edited by - ShmeeBegek on September 2, 2003 4:41:05 PM]
Hello ShmeeBegek,
I bet is because the * in list ::iterator it; is right next to >::
Try list ::iterator it.
Or like draqza stated your might need to put std::list ::iterator it.
Lord Bart
I bet is because the * in list ::iterator it; is right next to >::
Try list ::iterator it.
Or like draqza stated your might need to put std::list ::iterator it.
Lord Bart
quote:Original post by iaretony
SendMessage(list,LB_ADDSTRING,0,(LPARAM)(*it)->dat.name);
^ should be .
Iterators act like pointers, if you de-reference them, you no longer have a pointer, you have the object you''re pointing at, and therfore, must use . notation to access "dat" member.
No. Look at the definition of the iterator:
list<stTile*>::iterator it;
Dereferencing the iterator will return a
stTile*, so using the -> operator is correct to access the object pointed to''s members. [ Google || Start Here || ACCU || STL || Boost || MSDN || GotW || MSVC++ Library Fixes || BarrysWorld || E-Mail Me ]
Author
quote:
Hello ShmeeBegek,
I bet is because the * in list ::iterator it; is right next to >::
Try list ::iterator it.
Or like draqza stated your might need to put std::list ::iterator it.
Lord Bart
STL list class is a template class, it requires the template argument list, strange thing about this is that this exact line works perfectly in other member functions...
quote:
No. Look at the definition of the iterator:
list::iterator it;
Dereferencing the iterator will return a stTile*, so using the -> operator is correct to access the object pointed to''s members.
Exactly, I use iterators like this all the time
.Thanks for time / help, ~SPH
Author
I found the problem! The HWND argument''s name was list, so for some reason the compiler didn''t give an error and instead thought I was giving an HWND a template argument list.
Well anyways, the number of errors that SHOULD have produced would have been astronomical...
Thanks, ~SPH
This does not work either:
But this does:
Notice that you have a parameter named ''list'' to the function, that (and using namespace std) is the problem.
[How To Ask Questions|STL Programmer''s Guide|Bjarne FAQ|C++ FAQ Lite|C++ Reference|MSDN]
#include <list>using namespace std;void foo(int list){ list<int> bar;}But this does:
#include <list>void foo(int list){ std::list<int> bar;}Notice that you have a parameter named ''list'' to the function, that (and using namespace std) is the problem.
[How To Ask Questions|STL Programmer''s Guide|Bjarne FAQ|C++ FAQ Lite|C++ Reference|MSDN]
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