Stupid MS Calculator
Author
I have already posted this on another forum, but anyway.
MS Calculator does not perform one of the most elementary operations.
To the calculator in Windows, 0^0=1. Everyone knows that 0^0 is an undetermined operation. How could they do not know.
If they have a bug in such a small program like the calculator, I wonder what bugs lie in other programs.... e.g. Windows.
Anyway, if I were in charge at Microsoft, I would fire anyone who worked at the calculator.
Cya
0^0 == 1 ????!!!!!!!
I guess I could have been employed by Billy... Shit why haven''t I applied? Oh too bad...
Prog, Hex & Rock''n''Roll :
I don''t like the Prog but the Prog likes me.
Some nice poetry to sweeten your spirit and relax a bit before programming
I guess I could have been employed by Billy... Shit why haven''t I applied? Oh too bad...
Prog, Hex & Rock''n''Roll :
I don''t like the Prog but the Prog likes me.
Some nice poetry to sweeten your spirit and relax a bit before programming
IS EVERYONE HERE A FUCKING IDIOT???????????
0^0 IS NOT 1 !!!!!
FUCK!!!
GO IN MATHEMATICA AND TRY IT!!! IT IS THE ONLY SOFTWARE THAT DOES IT CORRECT!!! GO ASK YOUR MATH TEACHER!!! TAKE ANY RELIABLE CALCULUS BOOK!!!!
"0 at any power equals 0"
"any number raised at 0 equals 1"
The two fucking rules are colliding when we try to do 0^0. IT IS AN UNDETERMINED CASE SUCKERS!!!!
MORONS!!! Doesn''t anyone know SHIT about math on this forum???????
0^0 IS NOT 1 !!!!!
FUCK!!!
GO IN MATHEMATICA AND TRY IT!!! IT IS THE ONLY SOFTWARE THAT DOES IT CORRECT!!! GO ASK YOUR MATH TEACHER!!! TAKE ANY RELIABLE CALCULUS BOOK!!!!
"0 at any power equals 0"
"any number raised at 0 equals 1"
The two fucking rules are colliding when we try to do 0^0. IT IS AN UNDETERMINED CASE SUCKERS!!!!
MORONS!!! Doesn''t anyone know SHIT about math on this forum???????
Author
0^0!=1
For the ones that called me an idiot, read this:
If 0^0=1 than we can say that e^(0*ln[0])==1.
Therefore, we can say that e^(0*(-Infinity))==1
Which means that e^(0*-1*Infinity)==1
Which means that (e^0)*(e^Infinity)==1 (since 0*-1=0)
Which means that 1*(e^Infinity)==1
This means that 1*Infinity==1
This meanst that Infinity==1
Great job Einstein, you prooved that 1 is the biggest number in our Universe.
I hope you have the decency to admit you were wrong.
For the ones that called me an idiot, read this:
If 0^0=1 than we can say that e^(0*ln[0])==1.
Therefore, we can say that e^(0*(-Infinity))==1
Which means that e^(0*-1*Infinity)==1
Which means that (e^0)*(e^Infinity)==1 (since 0*-1=0)
Which means that 1*(e^Infinity)==1
This means that 1*Infinity==1
This meanst that Infinity==1
Great job Einstein, you prooved that 1 is the biggest number in our Universe.
I hope you have the decency to admit you were wrong.
This topic is closed to new replies.
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