#define KEY_DOWN(vKey) (GetAsyncKeyState(vKey) & 0x8000) ? true : false
Could someone explain this macro?
Author
Found this macro in a section of "OpenGL Game Programming."
& is used for a bitwise AND; here it is used if the most significant bit of a 16-bit word is set (and thus has nothing to do with pointers or addresses). Read up on bitwise logic (and binary/hexadecimal number representation if need be)!
Edit: That's what I get for posting without thinking: 0x8000 is, of course (as was corrected below) a 16-bit value, not a 32-bit value as I originally (and idiotically) claimed.
[edited by - Miserable on November 10, 2003 10:01:59 PM]
Edit: That's what I get for posting without thinking: 0x8000 is, of course (as was corrected below) a 16-bit value, not a 32-bit value as I originally (and idiotically) claimed.
[edited by - Miserable on November 10, 2003 10:01:59 PM]
GetAsyncKeyStats sets the highest bit of the returned WORD if the key is pressed, 0x8000 = 1000 0000 0000 0000 binary, the bitwise operator & does a ''bitwise and'' like so...
0101...
1000...
&___
0000 key not pressed
1101...
1000...
&___
1000 pressed
? is called the ternary operator
0101...
1000...
&___
0000 key not pressed
1101...
1000...
&___
1000 pressed
? is called the ternary operator
<< I''m especially curious about the "0x8000" part. It looks kind of like a memory address, but I''m not exactly an expert so I don''t know. >>
Its a bit-wise AND (&). The 0x8000 is binary I believe. You are masking the high bit to check for a key (or a VK code). The "?" is a conditional operator, kinda shorthand "if" statement.
Explained here
Game Programming Genesis, Part 3
Phil P
Its a bit-wise AND (&). The 0x8000 is binary I believe. You are masking the high bit to check for a key (or a VK code). The "?" is a conditional operator, kinda shorthand "if" statement.
Explained here
Game Programming Genesis, Part 3
Phil P
It calls a function called GetAsyncKeyState, passes as an argument the id of the key you want to test, and checks to see if it''s down. If it is, then the hi bit will be set, otherwise it wont. Like Miserable said, the & is used in a bitwise AND, and the ? is kinda like an IF statement, and : is used to seperate the results, depending on whether the IF is true. hope that clears it up 4 ya
(Stolen from Programmer One)
UNIX is an operating system, OS/2 is half an operating system, Windows is a shell, and DOS is a boot partition virus
(Stolen from Programmer One)
UNIX is an operating system, OS/2 is half an operating system, Windows is a shell, and DOS is a boot partition virus
0x8000 is just another notation for writing numbers. It's base 16, aka hexadecimal. As Miserable said read about bitwise operations and binary/hexadecimal numbers to understand how it works. After that read the MSDN docs for GetAsyncKeyState to see why the code does what it does.
And by the way, 0x8000 is a 16 bit value, not 32 bit.
Edit: Damn I'm slow
[edited by - Dobbs on November 10, 2003 9:14:12 PM]
And by the way, 0x8000 is a 16 bit value, not 32 bit.
Edit: Damn I'm slow
[edited by - Dobbs on November 10, 2003 9:14:12 PM]
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