Ok ok ok. I don''t have a lot of programming experience but I think this might work. I drew visuals too. Really this is all for my own benefit because until I put my ideas down on "paper" but I figured I''d have others take a look as well because frankly I don''t know if I''m even close to being right.
I want to be able to define a point in 3D space with x, y, and z coordinates, and then plot it on a 2D screen. I think I have this figured out. Please let me know if I''ve got this wrong.
Ok, first, I understand that the cone of vision for the uman eye is 60 degrees. I don''t suppose it really matters what I use for the 3D "camera" though, but I''ll go with 60 degrees just for the hell of it:
Alright. First thing I should mention is that the x, y, and z coordinates will be relative to the camera''s point of view. Later if I program any games with this (I have one in mind but I doubt I will finish it, because I never do), I will probably have all the points'' coordinates relative to the game world, and then convert the [i">visible[/i"> points in each from to be relative to the camera to make calculations easier. But for now, I have the field of view devided into 4 quadrantS:
Now suppose I plot a point in that field of view:
It''s 7 "units" on the z axis away from the camera, 2 units on the x axis to the right, and 2 units high on the y axis. Here''s another visual so you can see what I mean:
Now the basic idea here is that I want to know what angles (x and y) exist from the center of the point of view and then determine what percentage of the total 60-degree cone these angles take up. Here''s what I mean:
Now here''s a better picture with the useless stuff removed:
Knowing that the point is both 7 units away and 2 units high, I can easily figure out that the angle here is 15.9454 degrees. The other angle is also 15.9454 degrees because it has the same measurements, so no need to do the math again this time.
This tells me that the 15.9454-degree angle is 26.5756% of the total 60-degree cone.
When I apply that percentage to the vertical and horizontal resolution of the display, I find that it equals about 64 and 85 pixels. I have to round because duh you can light a fraction of a pixel. Anyway, so now I know how many pixels away from the center of the screen the point should be, right?
And now the finished point:
The one thing I did notice that was wrong while typing this is that the cone should probably be 60 degrees wide and 45 degrees tall, since the screen has a 4:3 aspect ratio. This method will probably make everything look a little smooshed. Other than that though it seems it should work. What do you think?
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