dp/dx is false: you derive w.r.t time
dp/dt = F = d(m*v)/dt = dm/dt*v + m*dv/dt = dm/dt*v + m*a
and this happened to be called "force"
as mass usually doesnt change over time dm/dt = 0, thus dp/dt = F = m*a
F = M*A
1 g is considered to be the gravity at sea level, so roughly 9.81 m/s^2
you get an acceleration of 2G, it''s basically roughly 20m/s^2. A sports car has an acceleration between 0.8 and 1.2 G. And if you''ve been in a Supra Twin Turbo 450 bhp, then you know 1G is still quite an experience, despite the fact that we are constantly pulled down by gravity
you get an acceleration of 2G, it''s basically roughly 20m/s^2. A sports car has an acceleration between 0.8 and 1.2 G. And if you''ve been in a Supra Twin Turbo 450 bhp, then you know 1G is still quite an experience, despite the fact that we are constantly pulled down by gravity
quote:Original post by Anonymous Poster
dp/dx is false: you derive w.r.t time
dp/dt = F = d(m*v)/dt = dm/dt*v + m*dv/dt = dm/dt*v + m*a
and this happened to be called "force"
as mass usually doesnt change over time dm/dt = 0, thus dp/dt = F = m*a
I fixed it, but its much simpler to just write out m * d(v)/dt instead of using the product rule since m is considered constant as you have in fact pointed out as well.
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