Ok. I know this is really easy but I just cant find it in my book and my compiler index isnt working. So heres the question. How can I round a double to an int? like 2.6 to 3? Oh and this is for C++ using visual studio .net 2003 Thanks for the help in advance. These are the two lines where Im using it maybe there is something wrong with them. Monster->LocationY = Monster->LocationY + round( ( double )Slope->SlopeY / Slope->SlopeX ); Monster->LocationX = Monster->LocationX + round( ( double )Slope->SlopeX / Slope->SlopeY ); I dont think so though the compiler error is: error C3861: ''round'': identifier not found, even with argument-dependent lookup

quote:Original post by BSMonkey
How can I round a double to an int? like 2.6 to 3?

The standard c library has ceil and floor that you can use to get a float/double that represents just the integer part. You will have to create your own round function (probably using ceil and/or floor ).

float float_number = 1.01;float floored_number = floor( float_number );// floored_number == 1.0float ceiled_number = ceil( float_number );// ceiled_number == 2.0int int_number = static_cast( float_number );// int_number == 1 

quote:Original post by BSMonkey
How can I round a double to an int? like 2.6 to 3?

You can add 0.5 to the number you want to round, then cast to int.

OK cool man that works greate thanks for the help. I hate it when I get stuck on this little stuff it just takes away my motivation but now I got it back so I can write a few more pages of code and hopefully I wont get stuck on something stupid