If you''ve got a local array it''s possible through the sizeof operator.

int list[] = { 1, 2, 3 };int count = sizeof(list) / sizeof(list[0]); 

But normally it doesn''t, you''ll have to keep track of it yourself.

Well if your talking about C strickly, there isn't way to tell from the array alone it's size except for as you said your self C style strings end with the null character '\0'. I guess this has something to do with with passing arrays in a function if thats the case you should also provide another parameter that will tell it's size like:

C style:

#include <stddef.h>void foobar(int array[], size_t size);

If you don't like this then you could make structure that has a pointer to some type and the size of the array when constructed, then make some functions that will create, destroy, manipulate them.

If your using C++ then its been recommended to avoid using raw dynamic arrays use a vector it provides a methods to find out stuff like it's size etc.

[edited by - snk_kid on June 9, 2004 5:26:47 AM]