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C++ - macro parameter substitution for string literals?

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Started by Painless July 06, 2004 04:34 PM

5 comments, last by DigitalDelusion 19 years, 9 months ago

Painless

126

Author

July 06, 2004 04:34 PM

Search didn't turn up much. Is there a way to use a parameter of a macro in a string literal? For example: #define FOO( BAR_ ) do_stuff( "BAR_" ); (so FOO( baz ) becomes do_stuff( "baz" );) Simply writing it like that doesn't seem to work - the macro parameter is ignored inside the string. Edit: code tags don't work the old way.. Edit n+1: whatever, I can't get any of them to work.

twanvl

512

July 06, 2004 04:37 PM

Yes, use a # prefix:
#define FOO(BAR) do_stuff(#BAR)
// FOO(baz) --> do_stuff("baz")

Anonymous

July 06, 2004 04:37 PM

#define FOO( BAR_ ) do_stuff ( #BAR_ )

DigitalDelusion

874

July 06, 2004 04:37 PM

what you wanted to say was:

#define FOO(x) do_stuff( #x)

HardDrop - hard link shell extension."Tread softly because you tread on my dreams" - Yeats

Fruny

1,658

July 06, 2004 04:37 PM

#define STR2(X) #X#define STR(X) STR2(X)#define FOO(BAR) do_stuff(STR(BAR))

Will work even if BAR is itself a macro.

"Debugging is twice as hard as writing the code in the first place. Therefore, if you write the code as cleverly as possible, you are, by definition, not smart enough to debug it." — Brian W. Kernighan

Painless

126

Author

July 06, 2004 04:38 PM

That was quick. Thanks.

DigitalDelusion

874

July 06, 2004 04:40 PM

Hehe four replies on the same minute...

HardDrop - hard link shell extension."Tread softly because you tread on my dreams" - Yeats

C++ - macro parameter substitution for string literals?

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