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casting as a pointer

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Well, your example makes no sense but

float r = 0.0f, *p = &r;
int k = 0, *y = &k;
cout << *p << endl;
p = (float*)y;
cout << *p << endl;

casts the value of y to the specified type (float*), and assigns the result to p. Thus, casting is the procedure of converting two, possibly unrelated, types. C++ provides many new keywords for doing this, though their use is often frowned upon and a sign of poor design or incorrect code.

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