Sign in to follow this  

casting as a pointer

This topic is 4844 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

If you intended to correct an error in the post then please contact us.

Recommended Posts

Well, your example makes no sense but

float r = 0.0f, *p = &r;
int k = 0, *y = &k;
cout << *p << endl;
p = (float*)y;
cout << *p << endl;

casts the value of y to the specified type (float*), and assigns the result to p. Thus, casting is the procedure of converting two, possibly unrelated, types. C++ provides many new keywords for doing this, though their use is often frowned upon and a sign of poor design or incorrect code.

Share this post


Link to post
Share on other sites

This topic is 4844 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

If you intended to correct an error in the post then please contact us.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

Sign in to follow this