Sign in to follow this  

somefunc-somefunc2 ???

This topic is 4823 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

If you intended to correct an error in the post then please contact us.

Recommended Posts

the -> operator is equivalent to

(*p).

it is used because pointers to classes are quite common in C/C++

for example

SomeClass *SomePointer = new SomeClass(whatever);

(*SomePointer).SomeMethod(); //This calls the SomeMethod method of SomeClass

SomePointer->SomeMethod(); //This does the same thing

its just shorthand

Share this post


Link to post
Share on other sites

This topic is 4823 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

If you intended to correct an error in the post then please contact us.

Create an account or sign in to comment

You need to be a member in order to leave a comment

Create an account

Sign up for a new account in our community. It's easy!

Register a new account

Sign in

Already have an account? Sign in here.

Sign In Now

Sign in to follow this