Rotating a light position
Author
I have a cube with a spotlight attatched to the bottom of it. The spotlight shines on anything thats directly below it.
Problem is, this cube is mobile. When I translate or rotate the cube the light must stay with it. Now I know how to keep the light with the cube during a translation, but I'm not sure how to keep the light with the cube after a rotation (using glRotatef() )
Is there a way to get the cube coordinates after a glRotate() is performed on it?
Or better yet, is there a way to rotate a point light source using glRotate()?
Thanks
why dont you multiply the lights position vector by the translated and rotated modelview matrix?
EDIT: or better yet, by the cube's transform matrix.
EDIT: or better yet, by the cube's transform matrix.
Author
How would I find the cubes transformation matrix?
or the translated and rotated modelview matrix?
or the translated and rotated modelview matrix?
Author
Actually, is there a way I can pull the cube coordinates from the modelview matrix? that would really be good, then I can just set
the position of the light that way.
the position of the light that way.
i think you should create your own matrix, its pretty easy using some lazy-ass openGL calls ;)
you'll need a mmult (matrix mult) function for matrix times vector.
anyway, something like that :D
you'll need a mmult (matrix mult) function for matrix times vector.
float m[16]; //our transform matrixvec3 lightPos = {...}; //in object space// first get OpenGL to generate our transformation matrixglPushMatrix();glLoadIdentity(); glTranslatef( cube.x, cube.y, cube.z ); glRotatef( cube.angleX, 1, 0, 0 ); // just for x axis ATM. // at this stage, OpenGL has done all the matrix math for us! glGetFloatv( GL_MODELVIEW_MATRIX, &m );glPopMatrix(); glPushMatrix(); lightPos = mmult(lightPos, m); glLightfv( GL_LIGHT0, GL_POSITION, &lightPos[0] ); glMultMatrixf(m); drawCube(); glPopMatrix();This topic is closed to new replies.
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