overloading global new operator
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can you overload the new global operator, using standart new operator inside the overloaded operator function body, without entering in an infinite recursive function ?
thnx
typedef void* (*global_new_ptr)(size_t);global_new_ptr global_new = ::operator new;void* operator new(size_t s){ // do some book keeping // allocate memory return (*global_new)(s);}Quote:Original post by Silly_con
still recursive
Well of course, thats not overloading that is just redefining it (well trying to and going into an infinite recusion) you wont something like this:
#include <new>#include <iostream>struct foo_t {};extern const foo_t foo; //no need to define it.inline void* operator new(size_t n, const foo_t&) throw() { std::cout << "MY NEW\n"; return ::operator new(n, std::nothrow);}inline void operator delete(void* ptr, const foo_t&) throw() { std::cout << "MY DELETE\n"; ::operator delete(ptr, std::nothrow);}int main() { int* int_ptr = new(foo) int(30); std::cout << *int_ptr << std::endl; operator delete(int_ptr, foo);}This topic is closed to new replies.
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