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athena

D3Dprimitive and line width

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I'm searching for a solution, not cpu intensive (no cos or sin if feasible) to draw lines with a width, can someone point me on something?

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Quote:
Original post by athena
thanks,
its only for Dx 9 it seems, any solution for Dx8 ?

No, you'll have to write it yourself. Off the top of my head (i.e. watch out!):
You should join the 2 endpoints using a quad with the required width. Given 2 2D endpoints, e1 and e2:
1) Let n be the perpendicular to the 2D line. n = normalize(<-(e1.y - e2.y), e1.x - e2.x>)
2) Let hw (half-width) = 0.5 * width
3) Let the 4 corners be c11, c12 (around e1), c21 and c22 (around e2). You can calculate them as follows:
c11 = e1 + hw * n;
c12 = e1 - hw * n;
c21 = e2 + hw * n;
c22 = e2 - hw * n;
4) Create a quad (using 2 triangles) with the given 4 corners

[edit]A couple of corrections[/edit]

[Edited by - Coder on December 17, 2004 11:08:25 PM]

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