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Sabonis

Simple Question

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Hey everyone, I have a quick question about arrays. Suppose I have the code float f[2]; f[0] = 10; f[1] = 20; for(int i = 0 ; i < sizeof(f); i++) cout << f << endl; return 0; I am guessing I am supposed to only get two lines of output... but im getting eight for some reason.. the first two are right but the rest are garbage values and such.. is there an explanation for this? Thanks!

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Yes, sizeof(f) = ( sizeof(float) * 2) = 4 * 2 = 8
Instead what you need to do is: i < 2 instead of sizeof(f).

Sizeof tells the memory size - not the physical array count.

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for(int i = 0; i < sizeof(f)/sizeof(f[0]); ++i)
This is only possible with arrays, not with pointers.

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