Euler and Taylor expansion
Euler integration formula is Taylor expansion using only 2 terms, good ?
how is done?:
taylor:
x = a
f(x) = f(a) + [f'(a)/1! ](x - a) + [f''(a)/2! ](x - a)^2 + ...
so:
if I call f like x
x(t0) = x0
x(t0 + h) = x0 + x'(t0)(t0 + h - t0) = x0 + x'(t0)*h
I don't know if I have done it good, if no, anyone can tell me how to deduce euler from taylor?
thnx
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