Sorry for the somewhat newb question

Graphics and GPU Programming Programming

Started by sathenzar February 09, 2005 08:00 PM

3 comments, last by sathenzar 19 years, 2 months ago

100

Author

February 09, 2005 08:00 PM

Hey everyone, sorry to bog this forum down with this newb posting, but I really don't understand these matrix functions. First off, I created a cube with the vertex buffer, no problems there. Then I moved the cube with the following code in the render function


D3DXMATRIX matTranslate, matFinal;
			D3DXMatrixIdentity(&matFinal);
			D3DXMatrixTranslation(&matTranslate, 0.0f, 0.0f, 0.0f);
			D3DXMatrixMultiply(&matFinal, &matFinal, &matTranslate);
			pd3dDevice->SetTransform(D3DTS_WORLD, &matFinal);

How does the cube know that you're telling it to move? All I see is functions that calculate matrix values. I don't see any movment assigned to the actual cube. Here's the complete render code below.


// Clear the backbuffer to a black color
			pd3dDevice->Clear( 0, NULL, D3DCLEAR_TARGET, D3DCOLOR_XRGB(255,255,255), 1.0f, 0 );

			pd3dDevice->BeginScene();
			D3DXMATRIX matTranslate, matFinal;
			D3DXMatrixIdentity(&matFinal);
			D3DXMatrixTranslation(&matTranslate, 0.0f, 0.0f, 0.0f);
			D3DXMatrixMultiply(&matFinal, &matFinal, &matTranslate);
			pd3dDevice->SetTransform(D3DTS_WORLD, &matFinal);
			pd3dDevice->SetStreamSource( 0, vertexBuffer, 0, sizeof(CUSTOMVERTEX) );
			pd3dDevice->SetFVF( D3DFVF_CUSTOMVERTEX );
			
			pd3dDevice->DrawPrimitive( D3DPT_TRIANGLESTRIP,  0, 2 );
			pd3dDevice->DrawPrimitive( D3DPT_TRIANGLESTRIP,  4, 2 );
			pd3dDevice->DrawPrimitive( D3DPT_TRIANGLESTRIP,  8, 2 );
			pd3dDevice->DrawPrimitive( D3DPT_TRIANGLESTRIP, 12, 2 );
			pd3dDevice->DrawPrimitive( D3DPT_TRIANGLESTRIP, 16, 2 );
			pd3dDevice->DrawPrimitive( D3DPT_TRIANGLESTRIP, 20, 2 );
			
			pd3dDevice->EndScene();

			// Present the backbuffer contents to the display
			pd3dDevice->Present( NULL, NULL, NULL, NULL );

Again, sorry and thanks for the help in advance.

adriano_usp

396

February 09, 2005 08:26 PM

Quote:I don't see any movment assigned to the actual cube.

Change the values in the D3DXMatrixTranslation function to move the cube.

Also:
Since the SetTransform method requires a initialized matrix, you can substitute:

D3DXMatrixIdentity(&matFinal);
D3DXMatrixTranslation(&matTranslate, tx , ty , tz );
D3DXMatrixMultiply(&matFinal, &matFinal, &matTranslate);
pd3dDevice->SetTransform(D3DTS_WORLD, &matFinal);

by:

D3DXMatrixTranslation(&matTranslate, tx , ty , tz );
pd3dDevice->SetTransform(D3DTS_WORLD, &matTranslate);

[Edited by - adriano_usp on February 9, 2005 8:26:29 PM]

Adriano Ribeiro

programmer_tom

214

February 09, 2005 08:32 PM

hey man.

you are setting the world transform here:

pd3dDevice->SetTransform(D3DTS_WORLD, &matFinal);

from this, DX's default vertex shader will deal with that matrix matFinal to transform the vertices ( you don't need to know more about shaders for now, just understand they magically do work for you ).

of course, you'll have to set the view and projection matrices too if yer gonna turn the camera around n stuff :)

also, the D3d matrix translation function will move your object around, but i believe it blows away the other elements of that matrix, so any rotations are lost ( i think i remember it being that way ).

we always just write functions to work with ._41, ._42, ._43

Anonymous

February 09, 2005 08:36 PM

yes you are correct... u r not giving the cube any instruction. the thing is that you are telling DirectX to transform (translate and/or rotate) whatever it is about to draw through this line:

pd3dDevice->SetTransform(D3DTS_WORLD, &matFinal);

YOU PASS THE MATRIX TO DIRECT3D

So here's what you do:

1. you first create a cube through the vertex buffer
2. Then you calculate some matrices. )Remember, that matrices are used to position and orient objects in 3D space)
3. Then you pass the matrix you have just calculated to Direct3D
4. Henceforth any thing that you draw will be transformed by the matrix that you passed to Direct3D

sathenzar

100

Author

February 09, 2005 09:35 PM

ok that makes sense now. Thanks for helping me on that, I appreciate it.

Sorry for the somewhat newb question

This topic is closed to new replies.

Popular Topics

Recommended Tutorials

Sorry for the somewhat newb question

This topic is closed to new replies.

Popular Topics

Recommended Tutorials

Reticulating splines