Yes.




I had a program that would do this, but I lost it during my latest hard-drive format. Its not too difficult, however.
Basically, you have a macro like so:

#define BITX(x) (x<<1)

(^The above is probably incorrect... Its meant to reference each bit.. i.e, BITX(4) would be the bit in location 4.)

then you loop through the byte and test if each bit is set (using &), then print out a 1 or 0 depending on its state.

Its been a long time since I did any bit-fiddling stuff, so my appologies if I left anything out, or if my description had any errors.

A. Buza: I hope you dont mind

    #define BITX(value, bitnr) (((value)>>(bitnr)) & 1)    

Ah, thanks!

Looking back at the macro I posted before... ugh.. it just multiplies by two...doh.