parseing with python
Author
ok i have try to look for find and parser in the help and can't seem to find what i am looking for. what i have it a doxufile that need to be built everynight and update the version number of the file automatically. now in the file the version looks like this:
PROJECT_NUMBER = "#first#.#second#.#thrid# #version#"
what i need to find out is how to find a certain text, replace it, and rewrite iot out to a different doxygen config file, can anyone help me?
Well, this is messy but I'm tired. It's not bad.
Which converted this:
to this:
Hopefully, that helps you out.
import redef run(): import re # Our regex, basically look for something that is 1 or more numbers in between #'s exp = re.compile( "#[0-9]+#") # The beginning of the line we're looking for lineBegin = "PROJECT_NUMBER = " # New replacement values firstRepl= 4 secondRepl = 19 thirdRepl = 25 versionRepl = 245 file = open("test.txt","r") outFile = open("testout.txt","w") replList = [] for line in file: if line[0:len(lineBegin)] == lineBegin: # Find all instances of matches of our regex, in iterator form iter = exp.finditer(line) for match in iter: # Match.span() returns a tuple of (beginningIndex, endingIndex) replList.append(match.span()) if len(replList) != 4: print "Error: All items not found." outFile.write(line) else: line = list(line) # We want them backwards as inserting at beginning will mess # up later indices replList.reverse() index = 4 for item in replList: if index == 4: # +1 and -1 to compensate for surrounding #'s line[item[0]+1:item[1]-1] = str(versionRepl) elif index == 3: line[item[0]+1:item[1]-1] = str(thirdRepl) elif index == 2: line[item[0]+1:item[1]-1] = str(secondRepl) elif index == 1: line[item[0]+1:item[1]-1] = str(firstRepl) index -= 1 outFile.write(''.join(line)) else: outFile.write(line) file.close() outFile.close()if __name__ == "__main__": run()Which converted this:
TEST #4# TEST #4PROJECT_NUMBER = "#1#.#2#.#3# #456#"SOME OTHER INFO 1 2 3 ##33## #4#to this:
TEST #4# TEST #4PROJECT_NUMBER = "#4#.#19#.#25# #245#"SOME OTHER INFO 1 2 3 ##33## #4#Hopefully, that helps you out.
Author
well now i want to replace #number_version# to like 0.0.1 and #name_version# to beta. it reads in from a templete file and then write out to a different file the is used my doxugen so the #number_varsion#, #name_version# is always there.how do i find #number_varsion#, #name_version#
First, let me clean up the code a bit:
In general, write an appropriate regex for the bit of text you want to find, and use the re module to do the search-and-replace. (In the sample code I match the whole line and output a whole replacement line manually instead).
Read the docs for the re module; if you're not familiar with regular expressions, you can [google] "regular expressions" and get pretty good results.
Although for simple literal strings like "#version_number#", this may be overkill. String objects in Python provide a 'replace' method that will return a version of self with the given replacement being done globally:
Thus you can build up a whole list of arguments for the replace - e.g. in a dict - and iterate through that:
import redef run(*replacements): # Make a single regex for the line we are looking for. # Look in the Python docs for regex syntax. line_matcher = re.compile( r"PROJECT_NUMBER = #[0-9]+#\.#[0-9]+#\.#[0-9]+# #[0-9]+#") infile = open("test.txt","r") outfile = open("testout.txt","w") for line in infile: if line_matcher.match(line): # This line has the format indicated by the line, so output the # replaced version. outfile.write("PROJECT_NUMBER = %s.%s.%s %s" % replacements) else: outfile.write(line) # no replacement infile.close() outfile.close()if __name__ == "__main__": run(4, 19, 25, 245)In general, write an appropriate regex for the bit of text you want to find, and use the re module to do the search-and-replace. (In the sample code I match the whole line and output a whole replacement line manually instead).
Read the docs for the re module; if you're not familiar with regular expressions, you can [google] "regular expressions" and get pretty good results.
Although for simple literal strings like "#version_number#", this may be overkill. String objects in Python provide a 'replace' method that will return a version of self with the given replacement being done globally:
>>> "foo".replace("o", "bar")'fbarbar'>>> Thus you can build up a whole list of arguments for the replace - e.g. in a dict - and iterate through that:
for line in infile: for key, value in replacements.items(): line = line.replace(key, value) outfile.write(line)
Author
ok the thing is i want to get rid of the ## that the number is inbetween and the first guys said is would look like:
#x number#.#x number#.#x number#
and well have version 1 looking like #1#.#0#.#0# looks really dumb. will what you said Zahlman get rid of the ##'s?
edit: what does this line of code do:?
if __name__ == "__main__":
[Edited by - 3dmodelerguy on March 20, 2005 5:39:00 PM]
#x number#.#x number#.#x number#
and well have version 1 looking like #1#.#0#.#0# looks really dumb. will what you said Zahlman get rid of the ##'s?
edit: what does this line of code do:?
if __name__ == "__main__":
[Edited by - 3dmodelerguy on March 20, 2005 5:39:00 PM]
Author
ok,i can get it to write out but not to that perticular line i can get it either at the bottom or the top. how do i change a line with another line?
Quote:Original post by 3dmodelerguyExecute the code after that line if that script is being launched itself (not imported etc).
if __name__ == "__main__":
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