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Tree Penguin

Quick matrix question, M1 = (M1*M2)*Inverse(M1)?

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Hi, for physics i multiply the matrix of a parent object (lets say M1) with that of a child (lets say M2), the resulting world-space matrix is then modified and i need to get M2 from that matrix (the transformation matrix in the space of M1), is that done by simply multiplying the resulting matrix with the inverse of matrix M1? I guess so but i'm just not sure, asking here might save me a lot of time :). Thanks in advance!

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You are almost correct. M2 = Inverse(M1)*(M1*M2) or M1 = (M1*M2)*Inverse(M2). Multiplying to the left is not the same as multiplying to the right (A*B != B*A).

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