Get exponent from number and base?
Author
Is there a way to get an exponent from a number and a base. For example, passing 32 and 2 would result in 5 because 2 to the power of 5=32.
Thanks
this works it seems
#include <iostream>
#include <math.h>
using namespace std;
int main(){
int tot = //number you want to find exponent of
int curr = 0; //keeps track of values
int x;
for(x = 0; curr <= tot; x++){
curr += pow(2,x);
}
x = x - 1;
cout << x << endl;
}
#include <iostream>
#include <math.h>
using namespace std;
int main(){
int tot = //number you want to find exponent of
int curr = 0; //keeps track of values
int x;
for(x = 0; curr <= tot; x++){
curr += pow(2,x);
}
x = x - 1;
cout << x << endl;
}
Simple algebra: log(x)/log(y) or ln(x)/ln(y) if you'd prefer :P
So your example would be log(32)/log(2) = 5
So your example would be log(32)/log(2) = 5
Author
Quote:Original post by load_bitmap_file
Simple algebra: log(x)/log(y) or ln(x)/ln(y) if you'd prefer :P
So your example would be log(32)/log(2) = 5
Log returns base-10 logarithm?
Quote:Original post by Raeldor
Log returns base-10 logarithm?
Doesn't matter, as long as you do log(x)/log(y), it will work.
Author
Quote:Original post by chaosgameQuote:Original post by Raeldor
Log returns base-10 logarithm?
Doesn't matter, as long as you do log(x)/log(y), it will work.
Is this one of these mathematical mysteries like PI? :P
Quote:Original post by Raeldor
Is this one of these mathematical mysteries like PI? :P
No. In fact, it's pretty trivial to prove if you try.
CM
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