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Genjix

calling interface functions with the same name

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class A
{
    public:
	virtual void D(int j) = 0;
}

class B : virtual public A
{
    public:
	virtual void D(int j);
}

class C : virtual public A
{
    public:
	virtual void D();
}

class E : public B , public C
{
	// ...
}


is there any way I can get C::D() to call B::D(int j) when in E, without changing the function names so they are different?

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I'm pretty sure you can't, then it'ld be impossible to make an object of the type C because it can't call "void B::D(int j)". If C needs to call a function inside B, C should inherit from B.

EDIT: Well know that I think about it I don't really know what you mean, does you mean this:

class C : public A
{
public:
virtual void D()
{
D(42);
}
}




or this:

class E : public C,public B
{
public:
virtual void D()
{
D(42);
}
}




The second example would be possible, but the first won't.

[Edited by - CTar on June 7, 2005 2:42:09 PM]

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Example:

class A
{
public:
virtual void D(int j) = 0;
};

class B : virtual public A
{
public:
virtual void D(int j)
{
printf("B::D Called\r\n");
};
};

class C : virtual public A
{
public:
virtual void D()
{
printf("C::D Called\r\n");
}
};

class E : public B , public C
{
public:
void test()
{
B::D(1);
C::D();
}
};

/// .. elsewhere
E e;
e.test();




output:
B::D Called
C::D Called

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Guest Anonymous Poster
You may also want to look at virtual inheritance for this situation.

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sorry for my horrible minimal wording.

basically i wanted to from within E call C::D() which calls the overriden A::D(int) or B::D(int).

but as some of you have said... this isn't possible unless I change the name of A::D(int)?

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Quote:
Original post by Genjix
sorry for my horrible minimal wording.

basically i wanted to from within E call C::D() which calls the overriden A::D(int) or B::D(int).

but as some of you have said... this isn't possible unless I change the name of A::D(int)?


Ah.. you want C::D to call B::D.. nope, can't be done.. or it would involve some serious hacks.

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I take it this is another 'deliberate' feature of C++ set by the standard? Is there any reason this is so?

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