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Grahf750

itoa and string variables

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I want to convert a number to a string itoa works with char*s and it is kind of a pain to convert everything from char*s to strings. Is there a better way to do it?

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Hi,

You can do the following i believe,

std::string myString = "15";

int ret = itoa( &myString[0] );

Give that a go.

ace

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Don't use itoa(), it is not ANSI, and not implemented on all the platforms.
Use sprintf
somethign like sprintf(str,"%i",number);

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Quote:
Original post by ace_lovegrove
std::string myString = "15";
int ret = itoa( &myString[0] );


That's atoi, and the correct way with a std::string would be atoi( myString.c_str() );

If you want itoa (integer->ascii) and using std::strings try using std::ostringstream

std::ostringstream ss;
ss << num;
std::string theStr = ss.str();

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Not sure why the conversion to string from char* is such a pain, but you really should be doing it in one of the suggested ways anyway - preferably with boost::lexical_cast, which is a general-purpose wrapper around the stringstream manipulation that will check for a few weird corner cases that come up when you try to make it really general :)

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