class MyCreator : public Creator
{
public:
virtual Product* MyCreator::Create( ProductId id )
{
if( id == YOURS ) return new MyProduct; // Switch YOURS for MINE
if( id == MINE ) return new YourProduct; // Switch MINE for YOURS
if( id == THEIRS ) return new TheirProduct; // New product Added
return Creator::Create(id);
}
};
//-----------------------------------------------------------------------------
// Main entry point for the test application...
//-----------------------------------------------------------------------------
void main( void )
{
MyCreator mCreator;
Product *mProd = mCreator.Create( MINE );
Product *yProd = mCreator.Create( YOURS );
Product *tProd = mCreator.Create( THEIRS );
mProd->printBarCode();
yProd->printBarCode();
tProd->printBarCode();
}
returns new object or just pointer ??
Author
Not quite sure about this..
does this return a new Object or Just a pointer to the new object?
//code from codesampler.com
Author
if it returns a pointer to the object... how do you delete the new object..?
delete *mProd
??
thanks
delete *mProd
??
thanks
just "delete mProd;".
new returns a pointer to an object, and delete takes that pointer and frees it.
Also, note that if you used the array version of new, like this:
MyProduct *mProd = new MyProduct[5];
you have to delete it with a special array delete:
delete[] mProd;
new returns a pointer to an object, and delete takes that pointer and frees it.
Also, note that if you used the array version of new, like this:
MyProduct *mProd = new MyProduct[5];
you have to delete it with a special array delete:
delete[] mProd;
Author
oh...
what about if you store a vector<Product*> and you get rid of one of them from the vector i.e.
..
pop_back()
clear()
will that delete the new object it holds a pointer to?
what about if you store a vector<Product*> and you get rid of one of them from the vector i.e.
..
pop_back()
clear()
will that delete the new object it holds a pointer to?
Quote:Original post by MTclip
oh...
what about if you store a vector<Product*> and you get rid of one of them from the vector i.e.
..
pop_back()
clear()
will that delete the new object it holds a pointer to?
Nope.
Check out the code in this thread for a good way to delete vectors of pointers (their "pointees", actually)
Quote:Original post by MTclip
oh...
what about if you store a vector<Product*> and you get rid of one of them from the vector i.e.
..
pop_back()
clear()
will that delete the new object it holds a pointer to?
No, it will simply remove the pointer from the vector. If you don't call delete on these pointers when you remove them, you'll get a memory leak. You can use smart pointers to handle the release of this memory for you when no more references to it exist. I personally would only use a smart pointer when an object should be responsible for controlling its own life span, but some people use them for just about everything. They're easier and safer, but they also have an additional overhead associated with them.
This topic is closed to new replies.
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