std::vector<std::string> commands;
while ( ! file.eof() )
{
char next[256];
file >> next;
commands.push_back(next);
}
SOLVED: C++, how do I convert a string to an int?
Author
Hi,
I'm reading text from a .txt file and storing the text in a vector of string objects. This works fine, but sometimes instead of text, the program will come across an integer. I want it to store the integers in a vector of ints instead of in the vector of strings.
This means I have to convert the string to an int. This is a problem in itself. I could probably work out how to do it manually by converting each digit to ascii etc, but is there a better way?
Also, how do I detect whether or not the string can be converted?
The strings are read in like this:
(Also, I seem to be using both old C string arrays and C++ string objects - is that OK? Is there a simpler way?)
[Edited by - darenking on August 2, 2005 2:11:56 AM]
atoi string to int
itoa int to string
std::string s;
int i = atoi(s.c_str());
there are several other functions for other datatypes see the msdn
itoa int to string
std::string s;
int i = atoi(s.c_str());
there are several other functions for other datatypes see the msdn
This works for strings
string s = "something from input";
if(s.find_first_of("013423456789") != string::npos){
cout << "Number Found " << endl;
}
if(s.find_first_of("abcdefghijklmnopqrstuvwxyz") != string::npos){
cout << "Letter found" << endl;
}
If the thing you read in has a # and letter then both will be found.
string s = "something from input";
if(s.find_first_of("013423456789") != string::npos){
cout << "Number Found " << endl;
}
if(s.find_first_of("abcdefghijklmnopqrstuvwxyz") != string::npos){
cout << "Letter found" << endl;
}
If the thing you read in has a # and letter then both will be found.
Quote:Original post by darenking
(Also, I seem to be using both old C string arrays and C++ string objects - is that OK? Is there a simpler way?)
You could have a string object instead of the char-array.
std::vector<std::string> commands; while ( ! file.eof() ) { std::string next; file >> next; commands.push_back(next); }Edit: As for converting string to int, you could use stringstream.
#include <sstream> while ( ! file.eof() ) { std::string next; file >> next; std::stringstream ss(next); int num; if(ss >> num) nums.push_back(num); else commands.push_back(next); }This is not failsafe. It will probably not give the result you want if the word read from the file is like "1a23", which will push back the '1' into nums and throw away the rest of the word.
[Edited by - Lajnold on August 1, 2005 4:57:53 PM]
Quote:Original post by Promit
boost::lexical_cast
Example:
#include <cassert>#include <string>#include <boost/lexical_cast.hpp>using namespace boost;int main () { assert( lexical_cast< int >( "42" ) == 42 ); assert( lexical_cast< std::string >( 42 ) == "42" );}
Reading from a stream and using std::basic_ios::eof() as the loop condition is wrong. You will, possibly, read once too many times. Use the read operation such as std::getline() as your loop condition. See:
http://www.parashift.com/c++-faq-lite/input-output.html#faq-15.5
// ville
http://www.parashift.com/c++-faq-lite/input-output.html#faq-15.5
// ville
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