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Separating template implementations (minor detail)

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I'm trying to separate a template implementation from the header file by including it in a .inl file. Everything works, but I don't really understand this... Here's a simple templated class:
template<class ObjType>
class TplClass {
public:
	typedef std::list<ObjType*> ObjList;
	void Add( ObjType* obj );
	ObjList* GetObjectList();
private:
	ObjList m_objList;
};
With the following implementation:
template<class ObjType>
void TplClass<ObjType>::Add( ObjType* obj ) {
	m_objList.push_back( obj );
};

template<class ObjType>
std::list<ObjType*>* TplClass<ObjType>::GetObjectList() {
	std::list<ObjType*>* objList = new std::list<ObjType*>;
	
	std::list<ObjType*>::iterator objItr = m_objList.begin();
	for ( ; objItr != m_objList.end(); ++objItr ) {
		objList->push_back( *objItr );
	};

	return objList;
};
This works, but changing the GetObjectList function to the code below doesn't, and I was wondering why.
template<class ObjType>
TplClass<ObjType>::ObjList* TplClass<ObjType>::GetObjectList() {
...
};
Thanks in advance.

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The compiler can't know whether TplClass<ObjType>::ObjList is a static member or a typedef until it knows what ObjType is. By default it assumes it is a static member. Use the typename keyword to let the compiler know that it is a typedef:
typename TplClass<ObjType>::ObjList* TplClass<ObjType>::GetObjectList() {

...

};

Enigma

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