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zlatko_bre_1985

Defines

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Is there way I can somehow put this in define #ifdef DEbuG debug::write(someString) #endif I tried this way but it gives error #define debugWrite(someString) #ifdef DEbuG debug::write(someString) #endif without #ifdef DEbuG and #endif code compiles ok. Is this possible somehow?

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A cleaner way would be to make the whole debug::write() function conditional with something like

#ifdef DEbuG
void debug::write( constr string& s ) {
// implement me
}
#else
inline void debug::write( const string& s ) {}
#endif

with a similar difference in the declaration, or even

inline void debug::write( constr string& s ) {
#ifdef DEbuG
// implement me
#endif
}



That way, you can just call debug::write() whenever you want, and when compiling without DEbuG defined the whole call will be optimized to nothing.

(edit) And now for the original problem... The preprocessor is a strange beast, and what you're trying to do can't work. You'll have to put the condition around the definition and have an appropriate "else" part, or the compiler will choke on an undefined debugWrite when DEbuG isn't defined.

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