void operator = (char* str)
{
m_str = str;
}
char* operator = (void)
{
return m_str;
}
char* operator << (void)
{
return m_str;
}
operator overloading
Author
Hi Im trying to learn operator overloading. This code here is fine.
But this code errors out saying error in function declaration; skipping function body, does anyone know why. Im a retard when it comes to this. Thanks.
operator=() and operator<<() are binary operators, you have to have something on the right hand side in order to use the = sign or <<. By declaring operator=(void) you try to declare operator=() as a unary operator. I'm not really sure what you are trying to accomplish with those two functions so I can't say how to fix them.
You can't overload operators for primitive types. Check out this page (and specifically, this question) for more info.
Edit: Sorry, misunderstood what you were trying to do
Edit: Sorry, misunderstood what you were trying to do
For the first one, you need to create a conversion operator. It looks like:
That being said, providing conversion operator are generally a bad idea. Implicit conversions can bite you in the rear. Prefer to write a member function that returns a pointer instead.
For the second one, you need a non-member overload of operator<< since the object on the left hand side is a std::ostream. It looks like:
You may need to friend the function to get the insides to compile.
class Class { public: operator char *() { return str; } char * str;};That being said, providing conversion operator are generally a bad idea. Implicit conversions can bite you in the rear. Prefer to write a member function that returns a pointer instead.
For the second one, you need a non-member overload of operator<< since the object on the left hand side is a std::ostream. It looks like:
std::ostream & operator<<(std::ostream & lhs, Class & rhs) { lhs << /* whatever */}You may need to friend the function to get the insides to compile.
To overload the stream insertion operator (the << operator) you will need to declare it as:
Typically this declaration is used within a class, allowing the user to print out various class information / data.
Now when you define the overloaded operator function, its defined like this:
ostream& operator<<(ostream&, ClassName);Typically this declaration is used within a class, allowing the user to print out various class information / data.
Now when you define the overloaded operator function, its defined like this:
ostream& operator<<(ostream& osObject, ClassName& name){ osObject << "Whatever info you want printed out here.";}Quote:Original post by cptrnet
std::string str = "Text";
This one is done by providing a constructor that takes a const char * argument, it has nothing to do with operator overloading. Though
std::string str;
str = "Text";
Is done by providing an overload of operator=() that takes a const char * argument like the first thing in your original post.
Author
Cool thanks alot SiCrane you've helped out of so many jams, And thanks to the other posters I will take a look at the page about overloading.
This topic is closed to new replies.
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