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vNistelrooy

Token-Pasting Operator (##)

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How can I force VC++ 2005 to keep the spaces before the operator? for example: #define foo(a) void bar(const ##a) The preprocessor converts foo(1) to void bar(const1).

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#define foo(t) void bar(const t a)
foo(char); // results in bar(const char a)


The only reason you'd use the ## is when you *don't* want the space; if you need the space, there's no reason to use the operator.

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as stated above if you want to preserve space simply dont use ## just
#define FOO(x,y) x y
#define BAR(x,y) x##y

FOO(foo,bar);//will become: foo bar
BAR(foo,bar);//will become: foobar

you'll only need to use ## when you want to get rid of whitespace effectivly creating a new token from two earlier seen ones.

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