Quote:O ,I see, but why return value can not be l value?
Because that's what the standard says. A function call evaluates to an r-value unless the function is declared as a reference type. Now, I'm not sure why you would want to do what it appears you are doing (other than for tinkering purposes) but you might try it this way:
int& get(int ii){int i = ii;return i;}int bar(int *i){return *i;}int i11 = bar(&get(4));
