// Loop through all letters and display them
// NOTE: 32 is a Space so don't display it normally
// NOTE: 127 is DEL so don't display it normally
// NOTE: 8 is Backspace
for (iIndex = 33; iIndex < 127; iIndex++)
{
cLetter = CHAR(iIndex);
cpLetter = &cLetter;
cpApp->mcFontRegular.Print(cpLetter, 50 + ((iIndex % iNumberOfLettersPerLine) * 20), 200 + ((iIndex / iNumberOfLettersPerLine) * 30), 0, 0, sDisplayedLettersTextColor);
}
How to pass a char as a char*
Author
Ok, basically I'm working on the entering high scores section of my game. Now I want to display the entire alphabit to the user so they can use the mouse to click on them.
Here's my code I'm using to display the characters I was visible:
Now, don't worry about the code after the cpLetter parameter of the Print function. Alright, the Print function takes a char* as it's first parameter, so what I'm doing is I'm using iIndex as the ASCII value of the letters, so a char is returned through CHAR(iIndex) to cLetter. I then just create a simple pointer to the cLetter (cpLetter) to pass in the Print function. This works, except that it prints the letter plus some other characters, sorta looks like "iiiiii". Now, even when I debug I see these extra characters.
I've been working on this for over an hour trying all sorts of different things, such as using character arrays, actually allocating cpLetter some memory and using it, making cpLetter[1] = '\n' (cpLetter[0] would equal the letter), type casting, etc. I just can't seem to get it to work. I always get those darn extra characters. Anyone know how I can do this or have any suggestions?
Thanks
It is not a NUL terminated string, so it is probably continuing to read until it finds a '0'.
Try this:
Try this:
// Loop through all letters and display them// NOTE: 32 is a Space so don't display it normally// NOTE: 127 is DEL so don't display it normally// NOTE: 8 is Backspace// Here we declare a character buffer of a size 2, 1 space// for the character, and one for the '\0' terminator.char cLetter[2];cLetter[1] = '\0'; // Set the NUL terminatorfor (iIndex = 33; iIndex < 127; iIndex++){ cLetter[0] = CHAR(iIndex); // Set the letter //cpLetter = &cLetter; WE HAVE NO NEED FOR A VARIABLE cpLetter cpApp->mcFontRegular.Print(&cLetter[0], 50 + ((iIndex % iNumberOfLettersPerLine) * 20), 200 + ((iIndex / iNumberOfLettersPerLine) * 30), 0, 0, sDisplayedLettersTextColor);}
It looks like IIII because there is no null terminator after the character and it will print until it finds one. What you want to do is create a string and make it hold just the one letter with a NULL terminator, like this.
cLetter = CHAR(iIndex);
char str[2];
str[0] = cLetter;
str[1] = '\0'; // NULL terminator
Hope that helps.
ace
cLetter = CHAR(iIndex);
char str[2];
str[0] = cLetter;
str[1] = '\0'; // NULL terminator
Hope that helps.
ace
Author
Oh my god, I knew that. For some reason I was thinking that '\n' was the null line terminator, not '\0'. Ahhhhh, I'm an idoit. I tried that right away too using '\n'. There goes an hour of my time for no reason. Thanks a lot though guys.
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