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Factoring Question

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How does factoring x(x+1)(2x+1) + 6(x+1)^2 end up as (x+1)[x(2x+1) + 6(x+1)]? Is there some shortcut for this that i'm not seeing?

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Should I multiply the first x into the (x+1) then try to factor it? Ive noted the x+1 but am not sure how to get to that second form

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Quote:
Original post by Gink
Should I multiply the first x into the (x+1) then try to factor it? Ive noted the x+1 but am not sure how to get to that second form


Try thinking of it like this,

a = x
b = x+1
c = 2*x+1

Then your original equation is

a*b*c + 6*b*b

Both terms are multiplied by b so you can factor it out

b*(a*c + 6*b)

And if you substitute for a, b, and c you get

(x+1)*(x*(2*x+1) + 6*(x+1))



-Josh

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