std::string temp;
for(;;)
{
cin>>temp;
if(temp=="CAR")
{ temp.clear();
//do stuff
else if(temp=="CDR")
{ temp.clear();
//do stuff
}
else if(temp=="EXIT")
{ temp.clear();
//do stuff
}
else
cout<<"Invalid Input";
}
String comparison
Author
Ok the first time through the loop it executes the code in the proper if statement. but 2nd time throught the loop it always just goes to the else and
prints out "Invalid Statement"
That shouldn't even compile, you are missing a closing barce after the first if statement.
Otherwise, it worked when I tested it. Care to show a bit more code?
jfl.
Otherwise, it worked when I tested it. Care to show a bit more code?
jfl.
Author
oh I just wrote that real quick, lemme copy the code. for example if you want to enter "CAR" you have to type in "CAR(" its using the ( to determine its the end of the string. but it works fine, first time around the loop, then it just goes to "input error"
char temp=0; string _T; for(;;) { cout<<endl<<"input: "; while(temp!='(') { temp=getchar(); if(temp=='(') break; else _T.push_back(temp); }temp=0; if(_T=="CAR") cout<<endl<<"CAR WORKS"; else if(_T=="CDR") cout<<endl<<"CDR WORKS"; else if(_T=="QUOTE") cout<<endl<<"QUOTE WORKS"; else cout<<"INPUT ERROR"; _T.clear(); }
I don't fully understand why you would want the user to type in CAR( and then try and look for the ( to determine the end of the string, because the string type in c++ lets you compare two strings using the == operator.
string _T;cout << "Type in CAR: " << endl;cin >> _T;if(_T == CAR) cout << "it works" << endl;else cout << "it doesn't" << endl;
before you loop back to the start of the loop try putting in cin.ignore(1)
It looks like you may be leaving a character on the input so that the next time around the loop it will pickup that character and the string won't be correct.
It looks like you may be leaving a character on the input so that the next time around the loop it will pickup that character and the string won't be correct.
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