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force problem

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I encountered this problem on a quiz in my physics class. The teacher has one way of doing it, which I believe is wrong. A box sits on an incline plane set at 35 degrees to the horizontal. Find the coefficient of friction if the box is being pulled up the ramp at a constant velocity (net force is zero). The box is 10 Kg. The force equations are: Fw = mg Fn = Fw * cos(angle) Fa = Fw * sin(angle) Ff = Fn * coefficient of friction My teacher believes the answer to the problem can be found by taking the tangent of the angle. He gets this by saying the force applied of the box is equal to the force friction Fa = Ff. From this equality, you can get tangent of the angle equals coeffient of friction. I and several of my fellow students believe he is wrong. We believe he is completely disregarding the force due to gravity which wants the box to move down the hill. So, in order for the box to move up the hill, the force moving the box up the hill must overcome the force that wants to move the box down the hill and the force that wants to keep the box in place (friction). Thus, Fup = Fdown + Ffriction. This problem does not give enough information to solve it that way. I don't see how my teacher is correct because his idea doesn't make sense in the real world or even with math. Any thoughts?

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xidis,

School related problems are not appropriate here. Please review the Forum FAQ. There are sites out there that are dedicated to homework/schoolwork help, and you should post your problem to one of those sites.

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