Quote:Original post by _Sigma
and why is ittest::returnAB( t ); // returns 40
Can it be? cheers!test.returnAB( t ); // returns 40,
No. test is a namespace, and as such uses the namespace resolution operator.
CM
Static var question
No. test is a namespace, and as such uses the namespace resolution operator.
CM
Quote:Original post by Conner McCloudQuote:Original post by _Sigma
and why is it test::returnAB( t ); // returns 40
Can it be test.returnAB( t ); // returns 40,? cheers!
No. test is a namespace, and as such uses the namespace resolution operator.
CM
Though you can use t.returnAB( t ); because t is an instance of the class test.
Right. You can use both because returnAB is a member of the class nonetheless, though it can resemble a namespace. [edit2] It should be t.returnAB, not test.returnAB.
Also, instance is a constant reference to test object ( const test &instance ). You could implement returnAB similarly using a pointer:
You would then use it like this:
I chose to use a reference because you cannot have an invalid reference (unless you do something really weird), and because I do not need the concept of "no reference" in that example.
[edit] It is not a namespace. Conner McCloud must have skimmed over the code rather rapidly ;). [edit3] I think I see what you mean, CM. Disregard.
jfl.
[Edited by - jflanglois on November 4, 2005 10:48:34 PM]
Also, instance is a constant reference to test object ( const test &instance ). You could implement returnAB similarly using a pointer:
static int returnAB( const test *instance ) { return instance->a * b;}You would then use it like this:
test t( 2 );test::returnAB( &t );I chose to use a reference because you cannot have an invalid reference (unless you do something really weird), and because I do not need the concept of "no reference" in that example.
[edit] It is not a namespace. Conner McCloud must have skimmed over the code rather rapidly ;). [edit3] I think I see what you mean, CM. Disregard.
jfl.
[Edited by - jflanglois on November 4, 2005 10:48:34 PM]
Quote:Original post by _Sigma
how did that become a namespace? :S
All classes have a namespace [of the same name] associated with them.
CM
Quote:Original post by Conner McCloudQuote:Original post by _Sigma
how did that become a namespace? :S
All classes have a namespace [of the same name] associated with them.
CM
Oh. Is it literally a namespace? How come I cannot use a namespace with the same name afterwards, then? [edit] Upon re-reading, I assume you mean that test.returnAB should be t.returnAB because test is effectively a namespace while he would need an instance to use that form?
Author
Ok, ya, I meant t.blah not test.blah
I'm a tad confused, and my code isn't compiling, as this is my first time using MS VC instead of Borland. I'll read this tomorrow when I'm awake :P
I'm a tad confused, and my code isn't compiling, as this is my first time using MS VC instead of Borland. I'll read this tomorrow when I'm awake :P
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