int main(int argc, char **argv)
{
	signed short signed_short = ~0; // int literals bits flipped to 1 then truncated & assigned to short.
	// visual bit pattern representation: 1111 1111  1111 1111

	// verify short is two bytes
	printf("sizeof(short) %d", sizeof(short)); // prints 2 - good

	signed_short &= 0x7fff; // mask out MSB
	// visual bit pattern representation: 0111 1111  1111 1111
	// print signed short max range:
	printf("signed short max range %d\n", signed_short); // should be: 32767 - prints: 32767 - good

	signed_short = ~0; // set all 16 bits to 1 again
	// visual bit pattern representation: 1111 1111  1111 1111

	// Now correct me if I'm wrong, in the following problem I will argue how I think mixing signed & unsigned
	// doesn't matter. Print max range for unsigned short with signed_short variable - ! mixing types !
	// continue reading...
	printf("unsigned short max range %u", signed_short); // should be: 65535 - what is printed: 4294967295
	// what is printed is the max range for an unsigned int. Now, I understand "%u" interprets signed_short
	// as an unsigned int (temporary conversion) the bit pattern for signed_short looks like
	// this: 1111 1111  1111 1111 after the "%u" conversion, it should look like 
	// this: 0000 0000  0000 0000  1111 1111  1111 1111 That's how I think it all works out and this last
	// printf call should have printed 65535 even though it's been interpreted as an int. Why? because the
	// left-most added WORD (as shown above) are all 0's and the right-most WORD are all 1's .. but it's as
	// if (or is) all the bits in the unsigned int interpretation are set to 1's:
	// 1111 1111  1111 1111  1111 1111  1111 1111 == 4294967295

	// declaring the variable as unsigned short solves the problem but I don't understand why declaring it signed
	// short should make a difference *here* since I'm not doing anything special on it like math where mixing
	// un/signed would probably make a difference. I'm only manually setting the bits and interpreting the variable
	// as an unsigned int in the last printf and it should behave as I described.

	getchar();
	return 0;
}