If you have a string you want to read in but don''t know it''s size, only that it ends in a 0, and waant to store it to [char String1;] is there any way to just add one byte to the current char list? I mean like: String1 += (char*) malloc(sizeof(char)); I know this doesn''t work, I''ve tried it. Is there a way? ----------------------------- Blue*Omega (Insert Witty Quote Here)

The way I do this is to allocate a buffer that you think will NEVER get filled i.e. 512 chars or something.

Read the string into that buffer...
find the length of the string.
Allocate the new buffer.
And do a strcpy.

easy as pie



Regards,
Nekosion

Thanks for the help! Nekosion, could you please explain a bit more? I think I know what your saying but would like an example.

-----------------------------

Blue*Omega

(Insert Witty Quote Here)

Use a temp string function as previously mentioned, (as long as you know your strings won''t go over a certain length). You have a temporary string buffer and call a function to get a pointer to a string of a certain size. The buffer is circular in nature so as you grab strings from it, it will eventually start over-writing itself. An obvious disadvantage if you need a whole pile of strings all at once.

#define MAX_TEMP_STRING_SPACE (512l)


char temp_string[MAX_TEMP_STRING_SPACE];
int temp_string_free = 0;


char *TempString( int size )
{
char *p;

if ( size > MAX_TEMP_STRING_SPACE ) ... error!!!!!!!
if ( MAX_TEMP_STRING_SPACE - temp_string_free < size ) temp_string_free = 0;

p = &temp_string[temp_string_free];
temp_string_free += size;

return p;
}



There''s really nothing wrong with:

char *new_string;

new_string = (char*)malloc( strlen(old_string) + 1 );
strcpy( new_string, old_string );

Apart from memory fragmentation... but that''s a different story ;-)


---Strange