Converting string or char* to wstring
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Is there any easy, built-in way to convert 8-bit strings (either std::string or char arrays/pointers) to a std::wstring. Or must I do it manually?
Since I program only Windows, I use MultiByteToWideChar. You can also use the ANSI function mbstowcs. Then if I need std::wstring i convert to that.
bool ConvertStringToUnicode(const char* cstr, wchar_t* wstr, int size){ // validate strings if(!cstr || cstr[0] == '\0') return false; if(!wstr || size <= 0) return false; // count number of elements to convert int elem = MultiByteToWideChar(CP_ACP, MB_PRECOMPOSED, cstr, -1, NULL, 0); if(!elem) return false; // convert string, clamping elem if buffer is size too small if(size < elem) elem = size; MultiByteToWideChar(CP_ACP, MB_PRECOMPOSED, cstr, -1, wstr, elem); return true;}
a standards compliant way, specialization for boost::lexical_cast:
#ifndef HG_LEXICAL_CAST_H__#define HG_LEXICAL_CAST_H__//SHERIEF_20050806_NOLIB//DEP_BOOST#include <string>#include <locale>#include <boost/lexical_cast.hpp>namespace boost{ template<> inline std::wstring lexical_cast<std::wstring, std::string>(const std::string& arg) { std::wstring result; std::locale loc; for(unsigned int i= 0; i < arg.size(); ++i) { result += std::use_facet<std::ctype<wchar_t> >(loc).widen(arg); } return result; } template<> inline std::string lexical_cast<std::string, std::wstring>(const std::wstring& arg) { std::string result; std::locale loc; for(unsigned int i= 0; i < arg.size(); ++i) { result += std::use_facet<std::ctype<wchar_t> >(loc).narrow(arg); } return result; }}#endif
wsprintf will convert narrow to wide character strings. %hs is the format specifier. from there, you can take your wide character pointer and make it into std::wstring.
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