struct A
{
int m_baseInt;
};


struct B : public A
{
B( int baseInt, int subInt ) : m_baseInt( baseInt ), m_subInt( subInt ){}
int m_subInt;
};

struct A
{
A( int baseInt ) : m_baseInt( baseInt ){}
m_baseInt;
};


struct B
{
B( int baseInt, int subInt ) : A( baseInt ), m_subInt( subInt ){}
m_subInt;
};

Quote:Original post by jujumbura
Hello all,

I have a question in regards to initializing a struct through the constructor. My situation was something like this:

struct A{int m_baseInt;};struct B : public A{B( int baseInt, int subInt ) : m_baseInt( baseInt ), m_subInt( subInt ){}int m_subInt;};

The compiler throws an error here. It tells me that "m_baseInt is not a member of B". This seems odd to me, aren't all member variables in structs public by default? So shouldn't I have access to a public member of my base class?

After poking around the net for initialization examples, I replaced it with the following code that I found:

struct A{A( int baseInt ) : m_baseInt( baseInt ){}m_baseInt;};struct B{B( int baseInt, int subInt ) : A( baseInt ), m_subInt( subInt ){}m_subInt;};

So, is this the way I should initialize the members of my base class? And if so, why don't I have access to those member variables when the constructor is executing?

I'd appreciate any insight.
Thanks much,

jujumbura

struct B : A // Public by default{   B(int baseInt, int subInt) : m_structA(baseInt), m_subInt(subInt)      A   m_structA;   int m_subInt;};

struct A{ A(int baseInt) : m_baseInt(baseInt)  {} int m_baseInt;};struct B : public A{ B(int baseInt, int subInt) : A(baseInt), m_subInt(subInt)  {}  int m_subInt;};