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Counting characters in string (C++)

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That depends a lot on what you have access to...

if you are using libraries with a string class then they all have a length function.

if you want to do it by hand.

int strlend(char * string)
{
int x = 0;
while (string[x] != '\0')
{
x++
}

return x;
}

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In C++, use the size or length method:


#include <iostream>
#include <string>

using namespace std;

int main()
{
string s1("GameDev.net");
cout << s1.length() << '\n';
cout << s2.size() << '\n';
}

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Quote:
Original post by TheTroll
That depends a lot on what you have access to...

if you are using libraries with a string class then they all have a length function.

if you want to do it by hand.

int strlend(char * string)
{
int x = 0;
while (string[x] != '\0')
{
x++
}

return x;
}


If i want to use the built in function, what do I write? I tried
count = lenght(name);
but it didn't work. I'm including the iostream library and string library.

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OK is this C or C++, because right now you're using C style strings(char*'s). If you want to use C strings, then the function you want is strlen. If you're using C++ then create an actual string object like in rohde's example.

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Quote:
Original post by rohde
In C++, use the size or length method:


#include <iostream>
#include <string>

using namespace std;

int main()
{
string s1("GameDev.net");
cout << s1.length() << '\n';
cout << s2.size() << '\n';
}


Umm... Why '\n' instead of endl which is the same length and easier to type.

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Quote:
Original post by Mike2343
Quote:
Original post by rohde
In C++, use the size or length method:


#include <iostream>
#include <string>

using namespace std;

int main()
{
string s1("GameDev.net");
cout << s1.length() << '\n';
cout << s2.size() << '\n';
}


Umm... Why '\n' instead of endl which is the same length and easier to type.


No reason other than habbit [smile] You might as well use endl - and it would probably be better style.

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