There is a function for converting between numbers and strings and different bases. It is itoa(). It converts an integer to a string. You specify your byte and a pointer to memory and the base you want, here 16, and the function will return that byte as a string, in base 16. Here is a cutout of the example code given in the VC++ 6.0 library. Hope this helps:


#include
#include

void main( void )
{
char buffer[20];
int i = 3445;
long l = -344115L;
unsigned long ul = 1234567890UL;

_itoa( i, buffer, 10 );
printf( "String of integer %d (radix 10): %s\n", i, buffer );

_itoa( i, buffer, 16 );
printf( "String of integer %d (radix 16): 0x%s\n", i, buffer );

_itoa( i, buffer, 2 );
printf( "String of integer %d (radix 2): %s\n", i, buffer );

_ltoa( l, buffer, 16 );
printf( "String of long int %ld (radix 16): 0x%s\n", l,
buffer );

_ultoa( ul, buffer, 16 );
printf( "String of unsigned long %lu (radix 16): 0x%s\n", ul,
buffer );
}

Output:

String of integer 3445 (radix 10): 3445
String of integer 3445 (radix 16): 0xd75
String of integer 3445 (radix 2): 110101110101
String of long int -344115 (radix 16): 0xfffabfcd
String of unsigned long 1234567890 (radix 16): 0x499602d2

Assuming you just want it converted to a string for display purposes, printf does what you need:

  char cVal = 69;printf("%0x\n", cVal);