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# Ellipse equation?

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(proc is the equivalent to a putpixel function. this is strictly out of the Allegro graphics library)

/* do_ellipse: *  Helper function for the ellipse drawing routines. Calculates the points *  in an ellipse of radius rx and ry around point x, y, and calls the  *  specified routine for each one. The output proc will be passed first a  *  copy of the bmp parameter, then the x, y point, then a copy of the d  *  parameter (so putpixel() can be used as the callback). */void do_ellipse(BITMAP *bmp, int x, int y, int rx, int ry, int d, void (*proc)()){   int ix, iy;   int h, i, j, k;   int oh, oi, oj, ok;   if (rx < 1)       rx = 1;    if (ry < 1)       ry = 1;   h = i = j = k = 0xFFFF;   if (rx > ry) {      ix = 0;       iy = rx * 64;      do {	 oh = h;	 oi = i;	 oj = j;	 ok = k;	 h = (ix + 32) >> 6; 	 i = (iy + 32) >> 6;	 j = (h * ry) / rx; 	 k = (i * ry) / rx;	 if (((h != oh) | | (k != ok)) && (h < oi)) {	    proc(bmp, x+h, y+k, d); 	    if (h) 	       proc(bmp, x-h, y+k, d);	    if (k) {	       proc(bmp, x+h, y-k, d); 	       if (h)		  proc(bmp, x-h, y-k, d);	    }	 }	 if (((i != oi) | | (j != oj)) && (h < i)) {	    proc(bmp, x+i, y+j, d); 	    if (i)	       proc(bmp, x-i, y+j, d);	    if (j) {	       proc(bmp, x+i, y-j, d); 	       if (i)		  proc(bmp, x-i, y-j, d);	    }	 }	 ix = ix + iy / rx; 	 iy = iy - ix / rx;      } while (i > h);   }    else {      ix = 0;       iy = ry * 64;      do {	 oh = h;	 oi = i;	 oj = j;	 ok = k;	 h = (ix + 32) >> 6; 	 i = (iy + 32) >> 6;	 j = (h * rx) / ry; 	 k = (i * rx) / ry;	 if (((j != oj) | | (i != oi)) && (h < i)) {	    proc(bmp, x+j, y+i, d); 	    if (j)	       proc(bmp, x-j, y+i, d);	    if (i) {	       proc(bmp, x+j, y-i, d); 	       if (j)		  proc(bmp, x-j, y-i, d);	    }	 }	 if (((k != ok) | | (h != oh)) && (h < oi)) {	    proc(bmp, x+k, y+h, d); 	    if (k)	       proc(bmp, x-k, y+h, d);	    if (h) {	       proc(bmp, x+k, y-h, d); 	       if (k)		  proc(bmp, x-k, y-h, d);	    }	 }	 ix = ix + iy / ry; 	 iy = iy - ix / ry;      } while(i > h);   }}/* ellipse: *  Draws an ellipse. */void ellipse(BITMAP *bmp, int x, int y, int rx, int ry, int color){   int clip, sx, sy, dx, dy;   if (bmp->clip) {      sx = x-rx-1;      sy = y-ry-1;      dx = x+rx+1;      dy = y+ry+1;      if ((sx >= bmp->cr) | | (sy >= bmp->cb) | | (dx < bmp->cl) | | (dy < bmp->ct))	 return;      if ((sx >= bmp->cl) && (sy >= bmp->ct) && (dx < bmp->cr) && (dy < bmp->cb))	 bmp->clip = FALSE;      clip = TRUE;   }   else      clip = FALSE;   do_ellipse(bmp, x, y, rx, ry, color, bmp->vtable->putpixel);   bmp->clip = clip;}

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Okay the general equation of an ellipse for any point is (maths version)

x(theta) = rx cos(theta)
y(theta) = ry sin(theta)
where 0 < theta < 2 pi
rx being the radius in the x, ry being the radius in the y.
So simply take the angle of your point, place it into the equation and find out if it is further from the origin than the point passed back by the equation.

This info was stolen from http://www.swin.edu.au/astronomy/pbourke/
check under geometry for nice 4D shapes and superellipsoid geometry

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There are some simpler ways to define it. Given radii along each axis -- rx, ry, rz...

The algebraic definition is...

 x^2     y^2     z^2----- + ----- + ----- = 1rx^2    ry^2    rz^2

The parametric definition requires 2 spherical angles and goes something like this...

   X = rx*cos(Phi)*Sin(Theta)   Y = ry*sin(Phi)   Z = rz*cos(Phi)*cos(Theta)

This does depend, though, on how your spherical angles are defined... You can define spherical angles based on which axis you rotate first, and all that. But the basic idea is the normal relationship between an X,Y,Z point and a rho, Phi, Theta point are multiplied by the corresponding axis radii.

- C.P.I. / ASMiNC

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Ah, yes. But has anyone figured out how to rotate an ellipse? You could take every point and run every point through the rotation equation...

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If gamma is the rotation about the origin then the new point would be
x = rx sin(theta)cos(gamma) + ry cos(theta)sin(gamma)
y = ry cos(theta)cos(gamma) + rx sin(theta)sin(gamma)

where 0 < theta < 2 pi

I used to have the sin(theta) and cos(theta) the other way around, but this way it normally produces a horizontal ellipse when rx is bigger than ry and gamma = 0
(I just did this off the top of my own head from the trigonometry I could remember, so if it's wrong....)

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It's wrong

.

.

.

.

just kidding, I have no idea

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What is equation for ellipsoid? I wanna determine if my point lies within ellips (with given horizontal and vertical radius), or not?

------------------
FlyFire/CodeX
http://codexorg.webjump.com

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Thanx a lot guys,
MikeD soultion is most appropriate for me.

------------------
FlyFire/CodeX
http://codexorg.webjump.com

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