# complex numbers

This topic is 4422 days old which is more than the 365 day threshold we allow for new replies. Please post a new topic.

## Recommended Posts

Hi all. I have that long of vector is z = 2i, then tangent of phi is 2/0, and dividing by zero is not allowed. I must be missing something. So what is the value of a and b? Thanks

##### Share on other sites
I assume you want to write it in polar coordinates.

If you think about it, draw the number in the complex plane, I'm sure you'll see that the angle is 90 degrees, i.e. pi/2 radians. Another way is to know the limits of tangens: lim a->inf ( tan( a / 2 ) ) = pi/2. Use a pocket calculator to draw the tan( x / 2 ) function if you're not convinced.

The Magnitude is just the euclidean distance of the real and imaginary parts.

mag = | real^2 + imag^2 | , in this case obviously equal to 2.

Thus in polar coordinates your number is:

2*exp(i*pi/2)

Thank you[smile]

1. 1
2. 2
3. 3
Rutin
22
4. 4
5. 5

• 13
• 19
• 14
• 9
• 9
• ### Forum Statistics

• Total Topics
632931
• Total Posts
3009292
• ### Who's Online (See full list)

There are no registered users currently online

×