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Calling a base class's version of a virtual function

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Take this code example:
class A
{
    virtual void foo()
    {
        cout << "a's foo";
    }
};

class B : public A
{
    virtual void foo()
    {
        cout << "b's foo";
    }
};

If, from within B::foo(), I want to call A::foo() on the this pointer (as in, treat this as an A and call this->foo()), how do I do that? Basically, how would I get this to happen:
B b;
//Somehow call A's version of foo() on B
b.foo();

with the output of "a's foo" I know you can somehow, but I've forgotten :) This obviously isn't what I really need it for, but thanks!

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