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# logarithm for integers

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I'm creating a little program that squares the numbers 1 to x. The problem I'm having is that I want the two columns(x and x^2) nicely lined up, which I have to do with the s.width(n) and setw(n) functions(it's an exercise from a book). This is how far I've gotten:
#include <iomanip>
#include <ios>
#include <iostream>
#include <math.h>

using namespace std;

int main()
{
const int numbers = 100;
const int biggestPlusOne = log10(numbers) + 2;

streamsize strwidth = cout.width();
for (int i = 1; i <= numbers; ++i)
{
int numSize = log10(i) + 1;
int ansSize = log10(i * i) + 1;
int width = biggestPlusOne + ansSize - numSize;
cout << i << setw(width) << i * i << endl;
}

return 0;
}

I hope the program is selfexplanatory... The idea is that 10logx + 1 gives me the number of digits IF it is rounded down. So in order to get rouded figures, I used integers as arguments. What I found out is that the function log10() doesn't accept integers. Does anybody have an idea on how to get around this issue?

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Ok, the problem has been solved:
#include <iomanip>#include <ios>#include <iostream>#include <math.h>using namespace std;int main(){	const int numbers = 100;	const int biggestPlusOne = (int)log10((double)numbers) + 2;	streamsize strwidth = cout.width();	for (int i = 1; i <= numbers; ++i)	{		int numSize = (int)log10((double)i) + 1;		int ansSize = (int)log10((double)i * i) + 1;		int width = biggestPlusOne + ansSize - numSize;		cout << i << setw(width) << i * i << endl;	}        setw(strwidth);	return 0;}

With typecasting I transformed the integers to doubles and the answers back to integers.

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