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only int

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so it accepts only numbers, no letters or other signs.


example
int num;
cout<< "enter number 1-5" << endl;

cin >> num; // before it gets assigned make sure the input is a number.


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You would probably have to do non-blocking input so that you can check the pressed key in real-time.

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Quote:
Original post by Dave
You would probably have to do non-blocking input so that you can check the pressed key in real-time.

You'd just have to do the same thing cin already does, just filtered so that letters and such are ignored. That would be really hard, and completely not worth the effort.

cout << "Enter 1-5. Please do not enter any letters or other signs." << endl;
cin >> num;
if(!cin) cout << "I said please :(" << endl;

CM

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Quote:
Original post by Conner McCloud
Quote:
Original post by Dave
You would probably have to do non-blocking input so that you can check the pressed key in real-time.

You'd just have to do the same thing cin already does, just filtered so that letters and such are ignored. That would be really hard, and completely not worth the effort.

cout << "Enter 1-5. Please do not enter any letters or other signs." << endl;
cin >> num;
if(!cin) cout << "I said please :(" << endl;

CM


Fair play.

I don't think i have ever tried it in C++ :/

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its not working for me?

#include "stdafx.h"
#include <iostream>
using namespace std;


int _tmain(int argc, _TCHAR* argv[])
{
int answer = 0;
while(answer != 8){
cout << "Enter number"<< endl;
cin >> answer;
if(!cin) {
cout << "I said please :(" << endl;
answer = 9;}

cout << "The answer is "<< answer <<endl;
}
return 0;
}

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MSDN exemple of cin do just that, but it use cin.fail() instead of !cin..... don't forget to .clear() on error ;)

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