only int
Author
i dont have my book with me!
What can i call that makes sure the input is and integer?
Author
so it accepts only numbers, no letters or other signs.
example
int num;
cout<< "enter number 1-5" << endl;
cin >> num; // before it gets assigned make sure the input is a number.
example
int num;
cout<< "enter number 1-5" << endl;
cin >> num; // before it gets assigned make sure the input is a number.
You would probably have to do non-blocking input so that you can check the pressed key in real-time.
Author
Im positive there is a simple call, i just dont remember it.
Maybe it was part of the Standard Template Library.
Maybe it was part of the Standard Template Library.
Quote:Original post by Dave
You would probably have to do non-blocking input so that you can check the pressed key in real-time.
You'd just have to do the same thing cin already does, just filtered so that letters and such are ignored. That would be really hard, and completely not worth the effort.
cout << "Enter 1-5. Please do not enter any letters or other signs." << endl;cin >> num;if(!cin) cout << "I said please :(" << endl;CM
Quote:Original post by Conner McCloudQuote:Original post by Dave
You would probably have to do non-blocking input so that you can check the pressed key in real-time.
You'd just have to do the same thing cin already does, just filtered so that letters and such are ignored. That would be really hard, and completely not worth the effort.cout << "Enter 1-5. Please do not enter any letters or other signs." << endl;cin >> num;if(!cin) cout << "I said please :(" << endl;
CM
Fair play.
I don't think i have ever tried it in C++ :/
Author
its not working for me?
#include "stdafx.h"
#include <iostream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
int answer = 0;
while(answer != 8){
cout << "Enter number"<< endl;
cin >> answer;
if(!cin) {
cout << "I said please :(" << endl;
answer = 9;}
cout << "The answer is "<< answer <<endl;
}
return 0;
}
#include "stdafx.h"
#include <iostream>
using namespace std;
int _tmain(int argc, _TCHAR* argv[])
{
int answer = 0;
while(answer != 8){
cout << "Enter number"<< endl;
cin >> answer;
if(!cin) {
cout << "I said please :(" << endl;
answer = 9;}
cout << "The answer is "<< answer <<endl;
}
return 0;
}
MSDN exemple of cin do just that, but it use cin.fail() instead of !cin..... don't forget to .clear() on error ;)
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