Quote:Original post by M2tM
Do brackets enable this to be safe?
i = (i++);
Nope. You need to add a sequence point. Brackets are used to make priority explicit, but in this case the priority would have been the same implicitly anyway. In this case, the value of i++ is evaluated before i = * anyway, but the side-effect of i++ need not be performed to get the value of i++ (in the case of ++i, this would have worked).
Quote:*edit: It seems it goes based on something called "sequence points" I'll look that up, but feel free to supply a description or links.
That's pretty simple: if two expressions are separated by a sequence point, the expression before it is entirely executed (along with its side-effects) before the expression after.
