dpadam450 2357 Report post Posted December 11, 2006 I always thought the dot product was just some weird number that related to angles between two vectors, but what does the dot product mean? My teacher talks about it all the time like it's supposed to be the length of projection or something. So the red part is what I'm thinking the dot product is giving (not the vector but the length of the vector). But even if this is true, in the upper right case, if I drew the red line on the top vector, the length of projection doesn't look like it could be 2. 0 Share this post Link to post Share on other sites
Brother Bob 10347 Report post Posted December 11, 2006 The length of the projection is given in units based on the length of the vector being projected onto.In the two upper cases, the vector being projected onto are both of length 1, so a dot product of 2 means the projected vector's length is 2/1=1. In the bottom case, the length of the vector projected onto is 2. The dot product is also 2, and the length of the projection is 2/2=1.So a longer vector you project onto, the larger the dot product. But to get the length, you have to divide by it's length. 0 Share this post Link to post Share on other sites
Vorpy 869 Report post Posted December 11, 2006 The length of the red line in the bottom left picture doesn't match the magnitude of the dot product for its vectors.The dot product of a vector with a unit vector gives the length of the projection of the vector onto the unit vector. To get the projection onto a non-unit vector, you must divide by the magnitude of the non-unit vector.The dot product is closely related to angles. The cosine of the angle between two vectors can be defined as the ratio of the dot product of the vectors to the product of their magnitudes. A dot B / |A|*|B|These different interpretations of the dot product are consistent with each other. 0 Share this post Link to post Share on other sites
dpadam450 2357 Report post Posted December 11, 2006 Ok so in the bottom left picture if I project the opposite way the length of (2,0)*(1,1) would be 2/ (1/radical(2) )? or the dot product divided by the lenght of vector (1,1) 0 Share this post Link to post Share on other sites
taby 1265 Report post Posted December 11, 2006 Your current assumption is pretty much correct. I personally think of it as 'how close are these two normalized vectors pointing in the same direction?'Normalized simply means that the vector has been dilated/contracted so that its length is 1. Of course, it still points in the same direction as its non-normalized form. To normalize a vector, we calculate its length and then divide each of its components by this value. If the length of the vector is 1, then it is already normalized. In some crowds, they call this a unit vector to denote that its length is 'of unity'.A dot product of -1 reveals that they are pointing in the completely opposite direction, and a dot product of 1 reveals that they are pointing in the same direction (they are technically the same vector). If the dot product is 0, then they are perpendicular.The following example vectors are already normalized:A = -1,0B = 1,0Dot product = -1*1 + 0*0 = -1 + 0 = -1A = 1,0B = 1,0Dot product = 1*1 + 0*0 = 1 + 0 = 1A = 1,0B = 0,1Dot product = 1*0 + 0*1 = 0 + 0 = 0In demonstration, for your first case:A = 1,1B = 1,0Step 1, Calculate the vector lengths:Length of A = Square root of dot product of A and itself = sqrt(1*1 + 1*1) = sqrt(2) = 1.4142135623730950488016887242097Length of B = sqrt(1*1 + 0*0) = sqrt(1) = 1Step 2, Normalize the vectors:A normalized = 1/1.414213,1/1.414213 = 0.707106,0.707106B normalized = 1/1,0/1 = 1,0 (we see now that it was already normalized, since it has not changed)Step 3, Calculate the dot product as usual using these normalized vectors:Dot product = 0.707106*1 + 0.707106*0 = 0.707106When dealing with normalized vectors like this, the dot product is always the cosine of the angle between them. So, to find the angle between 1,1 and 1,0, you would use arccos(0.707106).This stands to reason, since cos(180) gives us -1, cos(0) is 1, and cos(90) is 0, as described in paragraph 3.If ever the process to calculate the length of a vector seems strange, just remember the Pythagorean Theorem where c*c = a*a + b*b for a right triangle.WARNING: If you do not normalize the vectors beforehand, funny things happen and you may very well throw the Earth off its rotational axis, spinning us into either deep space or the fiery depths of the sun. :)[Edited by - taby on December 11, 2006 4:12:07 PM] 0 Share this post Link to post Share on other sites
CaveDweller 188 Report post Posted December 11, 2006 Quote:Original post by dpadam450Ok so in the bottom left picture if I project the opposite way the length of (2,0)*(1,1) would be 2/ (1/radical(2) )? or the dot product divided by the lenght of vector (1,1)The dot product of a unit vector IS the cosine which IS the projection of the vector lying on the x axis; if you look at it, the ratio of that projection and the hypotenuse (the top vector in this case) is the very definition of cosine. Calling the top vector in each of your diagrams 'u' and the bottom vector 'v', the dot product is also |u|* |v|* cos theta. And the length of the projection assuming u is not a unit vector will be |u| cos theta. So the length of the projection is also given by the dot product divided by the length of v ( |v| ).But all of this is just different calculations based on the definition of cosine, which is very clearly represented by the ratio of the lengths of the 'projected' vector and the original (top) vector in your diagrams. 0 Share this post Link to post Share on other sites